2b^3-4b^2-96b=

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Solution for 2b^3-4b^2-96b= equation:


Simplifying
2b3 + -4b2 + -96b = 0

Reorder the terms:
-96b + -4b2 + 2b3 = 0

Solving
-96b + -4b2 + 2b3 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '2b'.
2b(-48 + -2b + b2) = 0

Factor a trinomial.
2b((-6 + -1b)(8 + -1b)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'b' equal to zero and attempt to solve: Simplifying b = 0 Solving b = 0 Move all terms containing b to the left, all other terms to the right. Simplifying b = 0

Subproblem 2

Set the factor '(-6 + -1b)' equal to zero and attempt to solve: Simplifying -6 + -1b = 0 Solving -6 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + -1b = 0 + 6 Combine like terms: -6 + 6 = 0 0 + -1b = 0 + 6 -1b = 0 + 6 Combine like terms: 0 + 6 = 6 -1b = 6 Divide each side by '-1'. b = -6 Simplifying b = -6

Subproblem 3

Set the factor '(8 + -1b)' equal to zero and attempt to solve: Simplifying 8 + -1b = 0 Solving 8 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1b = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1b = 0 + -8 -1b = 0 + -8 Combine like terms: 0 + -8 = -8 -1b = -8 Divide each side by '-1'. b = 8 Simplifying b = 8

Solution

b = {0, -6, 8}

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